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If six digits number 25a64b is divisible by 11. Find the value of (a – b).1. 52. 43. 34. 7 |
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Answer» Correct Answer - Option 1 : 5 Given: Six digits number is 25a64b Concept used: Divisibility rule of 11, says, in a number when we add even place digits and subtract it from the sum of odd place digits, results will be either 0 or multiple of 11 Calculation: In digits 25a64b, the sum of odd place digits = 2 + a + 4 ⇒ 6 + a the sum of even place digits = 5 + 6 + b ⇒ 11 + b According to the divisibility rule of 11, The sum of odd place digits – the sum of even place digits = 0 ⇒ 6 + a – (11 + b) = 0 ⇒ a – b = 11 – 6 ⇒ a – b = 5 ∴ The value of (a – b) is 5. |
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