1.

If six digits number 25a64b is divisible by 11. Find the value of (a – b).1. 52. 43. 34. 7

Answer» Correct Answer - Option 1 : 5

Given:

Six digits number is 25a64b

Concept used:

Divisibility rule of 11, says, in a number when we add even place digits and subtract it from the sum of odd place digits, results will be either 0 or multiple of 11

Calculation:

In digits 25a64b, the sum of odd place digits = 2 + a + 4

⇒ 6 + a

the sum of even place digits = 5 + 6 + b

⇒ 11 + b

According to the divisibility rule of 11,

The sum of odd place digits – the sum of even place digits = 0

⇒ 6 + a – (11 + b) = 0

⇒ a – b = 11 – 6

⇒ a – b = 5

∴ The value of (a – b) is 5.



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