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If Σkr=1cos−1βr=kπ2 for any k≤1 and A=Σkr=1(βr)r, then limx→A(1+x)1/3−(1−2x)1/4x+x2 is equal to |
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Answer» If Σkr=1cos−1βr=kπ2 for any k≤1 and A=Σkr=1(βr)r, then limx→A(1+x)1/3−(1−2x)1/4x+x2 is equal to |
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