If Sn=n∑r=1r−1∑t=0(16n nCr rCt 4t), then the value of l, where l – InterviewSolution

1.	If Sn=n∑r=1r−1∑t=0(16n nCr rCt 4t), then the value of l, where l=∞∑n=1(1−Sn) is
Answer» If $S_{n} = n \sum r = 1 r - 1 \sum t = 0 (\frac{1}{6^{n}}^{n} C_{r}^{r} C_{t} 4^{t}),$ then the value of $l,$ where $l = \infty \sum n = 1 (1 - S_{n})$ is

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