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If Sn=n∑r=1r−1∑t=0(16n nCr rCt 4t), then the value of l where l=∞∑n=1(1−Sn) is

Answer»

If Sn=nr=1r1t=0(16n nCr rCt 4t), then the value of l where l=n=1(1Sn) is



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