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If solutbility of `CH_(3)` COOAg(s) in a buffer solution of pH equal to 5 is `1.414 xx10^(-y)` then calculate the value of y. Given : `K_(sp)(CH_(3)COOAg)=10^(-10),K_(a)(CH_(3)COOH)=10^(-5)` |
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Answer» Correct Answer - 5 `CH_(3)COOAg(s)iffCH_(3)COO^(-)(aq)+Ag^(+)(aq)` `CH_(3)COO^(-)(aq)+H_(2)O iff CH_(3)COOH+OH^(-)` `{:(x-z,,,,,,,,z,,,10^(-9)):}` `K_(h)=(10^(-14))/(10^(-5))=(zxx10^(-9))/(x-z)" "," "x-z=zimplies z=(x)/(2)` `K_(sp)=10^(-10)=(x-z)xx x" ",10^(-10)=(x)/(2)xx x` Solubility `x=sqrt(2)xx10^(-5)` Solubility `x=1.414xx10^(-y)` y=5 |
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