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If speed V, area A and force F are chosen as fundamental units, then the dimension of Young’s modulus will be(1) FA–1V0 (2) FA2V–1 (3) FA2V–2 (4) FA2V–3 |
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Answer» Answer is (1) FA–1V0 ∵ [Young’s modulus] = \(\Big[\frac{Force}{Area}\Big]\) ⇒ [Young’s modulus] = FA–1 ⇒ [Young’s modulus] = FA–1V0 |
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