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If `(-sqrt(2),sqrt2)` are cartesian co-ordinates off the point, then its polar co-ordinates are . . .A. `(1,( 4pi)/(3))`B. `(2,(3pi)/(4))`C. `(3,(7pi)/(4))`D. `(4,(5pi)/(4))` |
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Answer» Correct Answer - B We have `r cos theta = - sqrt(2)` and `r sin theta = sqrt(2)` `therefore r^(2) cos ^(2) theta + r^(2) sin theta = 2 + 2 = 4` `rArr^(2) )(cos ^(2) theta + sin^(2) theta) = 4` ` rArr r = pm and theta = tan^(-1)((sqrt(2))/(-sqrt(2)))` `theta = tan^(-1) (-1)rArr theta = (3pi)/(4)` `therefore ` Requrired polar co-ordinates is `( r , theta)` ` =(2,(3pi)/(4))` |
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