1.

If $\sqrt{4096}$ = 64 , then the value of $\sqrt{40.96}+\sqrt{0.4096}+\sqrt{0.004096}+\sqrt{0.00004096}$ up to two places of decimals is1). 7.092). 7.103). 7.114). 7.12

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I THINK OPTION 3 is the RIGHT ANSWER



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