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If stopping potentials corresponding to wavelengths `4000A` and `4500A` are 1.3 V and 0.9 V, respectively, then the work function of the metal isA. `0.3eV`B. `1.3eV`C. `1.8eV`D. `5eV` |
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Answer» Correct Answer - C `hgamma=w+K.E rArr hgamma =w+V_(0)e` |
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