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If sum_(i=0)^(2015) sum_(i=0)^(2015) C_(j)=k, then the value of (k+2)^(1//2016) is where (""^(n)C_(r) =0 AA n lt r & ""^(0)C_(0) =0} |
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Answer» `2^(1) + 2^(2) + 2^(3) +……….. + 2^(2015)` `=2(2^(2015)-1) =k` `=2^(2016) -2 =k rArr (k+2)^(1/2016) =2` |
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