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If sum_(i=1)^(n) x_(i)^(2) =300 and sum_(i=1)^(n) x_(i) =50 thenpossible value of n is :

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Solution :`sigma^(2) = (sumx_(i)^(2))/(N)-((sumx_(i))/(n))^(2)`
`=(300)/n -((50)/(n))^(2)=100/(n^2)(3n-25) gt C`
`implies n gt 25/3`.


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