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If sum of aquares of items =2,430, arithmctic mean =7, and number of items=12, find the coefficient of variation. |
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Answer» Given: `sumX^(2)=2,430, barX=7`, N=12 `sigma=sqrt((sumX)/(N)-(barx)^(2))` `=sqrt((2,430)/(12)-(7)^(2))=sqrt(202.5-49)` `=sqrt(153.5)=12.39` `CV=(sigma)/(barX)xx100` `=(12.39)/(7)xx100=177` Coefficient of Variation =1.77. |
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