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If sum of the 20 deviations from the mean is 100, then find the mean deviation. |
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Answer» \(\overline {X} = \cfrac{\sum(X_i\,-\,A)}{N} \) = \(\cfrac{\sum X_i}{N}\,-\,\cfrac AN\) Mean of deviations = Sum of deviations / No. of observations = \(\cfrac AN\) = 100/20 = 5 |
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