1.

If sum of the 20 deviations from the mean is 100, then find the mean deviation.

Answer»

\(\overline {X} = \cfrac{\sum(X_i\,-\,A)}{N} \) = \(\cfrac{\sum X_i}{N}\,-\,\cfrac AN\)

Mean of deviations = Sum of deviations / No. of observations

 = \(\cfrac AN\) =  100/20 = 5



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