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If sum of the infinite G.P., p,,3. is , the val |
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Answer» first term is = p and C.R = 1/P so, sum of infinite terms of G.P = a/1-R => p/(1-1/p)= 9/2=> p²/(p-1) = 9/2=> 2p² = 9p -9=> 2p² -9p +9 = 0=> 2p²-6p-3p+9 = 0=> 2p(p-3) -3(p-3) = 0=> (2p-3)(p-3) = 0=> p = 3/2 , 3 |
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