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If `sum_(r=0)^(203)((r^(2)+2)(r+1)!+2r(r+1)!)=a!-2(b)` (where `a,b in N`), then `a-b` is equal to_____ |
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Answer» Correct Answer - 1 `(r^(2)+2)(r+1)!+2r(r+1)!=(r+1)(r+2)!-r(r+1)!` |
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