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if `tan^(-1)(2x)+tan^(-1)(3x)=npi+(pi)/(4),nepsilonI` then number of order pair (s) `(n,x)` is (are)` |
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Answer» Correct Answer - 2 `(2x+3x)/(1-6x^(2))=1,6x^(2)+5x-1=0x=-1,(1)/(6)` `x=-1,-3(pi)/(4)=npi+(pi)/(4)` `impliesn=-1,x=(1)/(6),n=0` |
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