If tan-1(x2 +y2) = α then dy/dx is equal to(1) xy(2) - xy(3) -x/y(4

1.	If tan-1(x2 +y2) = α then dy/dx is equal to(1) xy(2) - xy(3) -x/y(4) x/y
Answer» Correct option (3) -x/y Explanation: tan^-1 (x² +y²) = α ⇒ x² + y²= tan α Differentiating w.r.t. x, we get 2x +2y dy/dx = 0 ⇒ dy/dx = -x/y.

If tan-1(x2 +y2) = α then dy/dx is equal to(1) xy(2) - xy(3) -x/y(4) x/y

Answer»

Correct option (3) -x/y

Explanation:

tan^-1 (x² +y²) = α

⇒ x² + y²= tan α

Differentiating w.r.t. x, we get 2x +2y dy/dx = 0

⇒ dy/dx = -x/y.

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If tan-1(x2 +y2) = α then dy/dx is equal to(1) xy(2) - xy(3) -x/y(4) x/y

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