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If tan 2A = cot(A – 18°), where 2A is an acute angle, find the value of A. |
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Answer» tan 2Å = cot(A – 18°) ⇒ 90 – 2A = A – 18° ⇒ 3A =108° ⇒ A =36 tan2A= cot (A-18)=> cot(90-2A)=cot(A-18) => 90-2A=A-18 => 2A+A=90+18 =>3A=108 =>A = 108/3=36 |
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