1.

If tan `4theta = cot 3 theta ` , then general value of `theta`-A. `(2n+1)(pi)/(14),n ne 3k`B. `(2n+1)(pi)/(6)`C. `(2n+1)(pi)/(14)`D. `(2n+1)(pi)/(14),n ne 8 k`

Answer» Correct Answer - C
tan `4 theta= cot 3 theta`
`thetane(2n+1)(pi)/(8)`
`theta ne (npi)/(3)`
` theta =((2n+1)pi)/(2(4+3))`
no condition is applicable
hence ` theta =((2n+1)pi)/(14)`


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