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If tan `4theta = cot 3 theta ` , then general value of `theta`-A. `(2n+1)(pi)/(14),n ne 3k`B. `(2n+1)(pi)/(6)`C. `(2n+1)(pi)/(14)`D. `(2n+1)(pi)/(14),n ne 8 k` |
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Answer» Correct Answer - C tan `4 theta= cot 3 theta` `thetane(2n+1)(pi)/(8)` `theta ne (npi)/(3)` ` theta =((2n+1)pi)/(2(4+3))` no condition is applicable hence ` theta =((2n+1)pi)/(14)` |
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