1.

If `(tan(A+B+C))/(tan(A-B+C))=(tanC)/(tanB)` then `sin2A+sin2B+sin2C` is equal to_______

Answer» `(sin(A+B+C).cos(A-B+C))/(sin(A-B+C)cos(A+B-C))=(sinCcosB)/(sinBcosC)`
`implies(sin2A+sin(2B-2C))/(sin2A-sin(2B-2C))=(sinCcosB)/(sinBcosC)`
Use `C` and `D` rule will get `sin2A+sin2B+sin2C=0`


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