1.

If \( \tan A=\frac{1}{2} \), and \( \tan B=\frac{1}{3} \), find the value of \( (A+B) \)

Answer» tanA=1/2 , tanB=1/3

Now using the following formula

tan(A+B)= (tanA+tanB)/(1-tanA.tanB)

tan(A+B)=(1/2+1/3)/{1-(1/2)(1/3)}

tan(A+B)={(3+2)/6}/{1-1/6}

tan(A+B)= (5/6)/(5/6)

tan(A+B)=1

(A+B)=arctan(1)

A+B=45°


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