Saved Bookmarks
| 1. |
If tan (x+y) = e^(x+y), then (dy)/(dx): |
|
Answer» is always equal to -1 ` RARR sec^2 (x+y) [1+(dy)/(dx)]=e^(x+y)[1+(dy)/(dx)]` ` therefore (dy)/(dx) = -1 "or " 1+e^(2(x+y)) = e^(x+y)` (not possible) ` 1+t^2 -t = 0 rArr (t - 1/t)^2 +3/4 =0 therefore (dy)/(dx) = -1 AA x,y` |
|