1.

If tan (x+y) = e^(x+y), then (dy)/(dx):

Answer»

is always equal to -1
may or may not be equal to -1
`(dy)/(DX) `cannot be obtained
None of these

Solution :`TAN (X + y) = e^(x+y)`
` RARR sec^2 (x+y) [1+(dy)/(dx)]=e^(x+y)[1+(dy)/(dx)]`
` therefore (dy)/(dx) = -1 "or " 1+e^(2(x+y)) = e^(x+y)` (not possible)
` 1+t^2 -t = 0 rArr (t - 1/t)^2 +3/4 =0 therefore (dy)/(dx) = -1 AA x,y`


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