If tanα=1√x(x2+x+1),tanβ=√x√x2+x+1 and tanγ=√x−3+x−2+x� – InterviewSolution

1.	If tanα=1√x(x2+x+1),tanβ=√x√x2+x+1 and tanγ=√x−3+x−2+x−1, where x≠0, then α+β is
Answer» If $tan α = \frac{1}{\sqrt{x (x^{2} + x + 1)}}, tan β = \frac{\sqrt{x}}{\sqrt{x^{2} + x + 1}}$ and $tan γ = \sqrt{x^{- 3} + x^{- 2} + x^{- 1}}$ , where $x \neq 0$ , then $α + β$ is

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