1.

If tanA = \(\frac{3}{4}\), find the value of \(\frac{1}{sinA}+\frac{1}{cosA}\)

Answer»

tanA = \(\frac{3}{4}\) = \(\frac{3k}{4k}\)

sinA = \(\frac{3k}{5k}\) = \(\frac{3}{5}\), cosA = \(\frac{4k}{5k}\) = \(\frac{4}{5}\)

\(\frac{1}{sinA}+\frac{1}{cosA}\)

= \(\frac{5}{3}+\frac{5}{4}\)

\(\frac{(20+15)}{12}\)

\(\frac{35}{12}\)



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