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If tanA = \(\frac{3}{4}\), find the value of \(\frac{1}{sinA}+\frac{1}{cosA}\) |
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Answer» tanA = \(\frac{3}{4}\) = \(\frac{3k}{4k}\) sinA = \(\frac{3k}{5k}\) = \(\frac{3}{5}\), cosA = \(\frac{4k}{5k}\) = \(\frac{4}{5}\) \(\frac{1}{sinA}+\frac{1}{cosA}\) = \(\frac{5}{3}+\frac{5}{4}\) = \(\frac{(20+15)}{12}\) = \(\frac{35}{12}\) |
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