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If tanα = P, then cos2α is equal to(A) \(\frac{1-P^2}{1+P^2}\)(B) \(\frac{2P}{1-P^2}\)(C) \(\frac{2P}{1+P^2}\)(D) \(\frac{1+P^2}{2P}\) |
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Answer» Correct option is: (A) \(\frac{1-P^2}{1+P^2}\) |
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