If tanθ = -1 then find the value of \(\frac{sec\theta+cosec\theta}{

1.	If tanθ = -1 then find the value of \(\frac{sec\theta+cosec\theta}{cos\theta+sin\theta}\)(1) 0 (2) 1 (3) −√2 (4) √2
Answer» (1) 0 tanθ = -1 \(\frac{sec\theta+cosec\theta}{cos\theta-sec\theta}\) = \(\frac{cosec\theta\,(tan\theta+1)}{cos\theta\,(1-tan\theta)}\) = 0

If tanθ = -1 then find the value of \(\frac{sec\theta+cosec\theta}{cos\theta+sin\theta}\)(1) 0 (2) 1 (3) −√2 (4) √2

Answer»

(1) 0

tanθ = -1

\(\frac{sec\theta+cosec\theta}{cos\theta-sec\theta}\) = \(\frac{cosec\theta\,(tan\theta+1)}{cos\theta\,(1-tan\theta)}\) = 0

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If tanθ = -1 then find the value of \(\frac{sec\theta+cosec\theta}{cos\theta+sin\theta}\)(1) 0 (2) 1 (3) −√2 (4) √2

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