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If tanx+tan(x+π3)+tan(x+2π3)=3, prove that 3tan x−tan3x1−3tan2 x=1. Or If sinθ=nsin(θ+2α), prove that tan(θ+α)=1+n1−ntanα. |
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Answer» If tanx+tan(x+π3)+tan(x+2π3)=3, prove that 3tan x−tan3x1−3tan2 x=1. Or If sinθ=nsin(θ+2α), prove that tan(θ+α)=1+n1−ntanα. |
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