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If ten objects are distributed at random among ten persons, then find the probability that at least one of them will not get any object. |
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Answer» Each of the 10 objects can be given to any one of the 10 persons. So, total number of ways = `10^(10)` The number of ways of distribution in which each one gets exactly one object is `10!`. So, the number of ways of distribution in which at least one of them does not get any object is `(10^(10) - 10!)`. `therefore` Required probability = `(10^(10) - 10!)/(10^(10))` |
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