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If ten volumes of dihydrogen gas react with five volumes of dioxygen gas, how many volumes of water vapour would be produced? |
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Answer» Solution :`underset("2 volumes")(2H_(2)(g)) + underset("1 VOLUME")(O_(2)) to underset("2 volumes")(2H_(2)O) (g)` Two volumes of `H_2` react with one volume of `O_(2)` to produce two volumes of WATER vapour. Hence, 10 volumes of `H_2` will react completely with 5 volumes of `O_(2)` to produce 10 volumes of water vapour. |
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