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If ten volumes of dihydrogen gases react with five volumes of dioxygen gases that, how many volumes of water vapour would be produced ? |
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Answer» Solution :`underset(2 volumes)(2H_(2(G))) + underset(1 volume)(O_(2(g))) rarr underset(2 volumes)(2H_(2)O)` Thus 2 volumes of `H_(2)`REACTS with 1 volume of `O_(2)` to produce 2 volumes of `H_(2)O_((g))`. `:.` 10 volumes of `H_(2)`WOULD react with 5 volumes of `O_(2)` to produce 10 volumes of `H_(2)O_((g))` , Thus 10 volumes of `H_(2)O` will be produced. |
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