If θ=tan−1d1+a1a2+tan−1d1+a2a3+⋯+tan−1d1+an−1an, where a1,a – InterviewSolution

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1.	If θ=tan−1d1+a1a2+tan−1d1+a2a3+⋯+tan−1d1+an−1an, where a1,a2,a3,⋯an are in A.P. with common difference d, then tanθ=
Answer» If $θ = t a n^{- 1} \frac{d}{1 + a_{1} a_{2}} + t a n^{- 1} \frac{d}{1 + a_{2} a_{3}} + \dots + t a n^{- 1} \frac{d}{1 + a_{n - 1} a_{n}}$ , where $a_{1}, a_{2}, a_{3}, \dots a_{n}$ are in A.P. with common difference d, then $t a n θ =$

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