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If the amplitude ratio of two sources producing interference is 3 : 5, the ratio of intensities at maxima and minima isA. `25:16`B. `5:3`C. `16:1`D. `25:9` |
Answer» Correct Answer - C In interference, `I_(max)=(sqrt(I_(1))+sqrt(I_(2)))^(2)` `"while " I_(max)=(sqrtI_(1)-sqrt(I_(2)))^(2)` `"So "I_(max)/I_(min)=(sqrt(I_(1))+sqrtI_(2))^(2)/((sqrt(I_(1))-sqrt(I_(2)))^(2))` `=(A_(1)+A_(2))^(2)/((A_(1)-A_(2))^(2))` :. Given `A_(1)/A_(2)=3/5` `:. I_(max)/I_(min)=((3+5)^(2))/((3-5)^(2))=16/1` |
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