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If the amplitude ratio of two sources producing interference is 3 : 5, the ratio of intensities at maxima and minima isA. `25:16`B. `5:3`C. `16:1`D. `25:9`

Answer» Correct Answer - C
In interference,
`I_(max)=(sqrt(I_(1))+sqrt(I_(2)))^(2)`
`"while " I_(max)=(sqrtI_(1)-sqrt(I_(2)))^(2)`
`"So "I_(max)/I_(min)=(sqrt(I_(1))+sqrtI_(2))^(2)/((sqrt(I_(1))-sqrt(I_(2)))^(2))`
`=(A_(1)+A_(2))^(2)/((A_(1)-A_(2))^(2))`
:. Given `A_(1)/A_(2)=3/5`
`:. I_(max)/I_(min)=((3+5)^(2))/((3-5)^(2))=16/1`


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