1.

If the angle alpha between two forces of equal magnitude is reduced to (alpha-pi//3), then the magnitude of their resultant becomes (alpha-pi//3),times of the earlier one. The angle alpha is

Answer»

`pi//2`
`2pi//2`
`pi//4`
`4pi//5`

Solution :`sqrt(F^(2)+F^(2)+2F^(2)cos(ALPHA(pi)/(3)))=sqrt3xx[sqrt(F^(2)+F^(2)+2F^(2)cosalpha)]`
on solving `,alpha=(2pi)/(3)"""]"`


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