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If the angle `alpha` between two forces of equal magnitude is reduced to `(alpha-pi//3),` then the magnitude of their resultant becomes `(alpha-pi//3),`times of the earlier one. The angle `alpha` isA. `pi//2`B. `2pi//2`C. `pi//4`D. `4pi//5` |
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Answer» Correct Answer - B `sqrt(F^(2)+F^(2)+2F^(2)cos(alpha(pi)/(3)))=sqrt3xx[sqrt(F^(2)+F^(2)+2F^(2)cosalpha)]` on solving `,alpha=(2pi)/(3)" ""]"` |
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