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If the angle of projection of a projector with same initial velocity exceed or fall short of `45^(@)` by equal amount `alpha`, then the ratio of horizontal rages isA. `1:2`B. `1:3`C. `1:4`D. `1:1` |
Answer» Correct Answer - D Given,`theta_(1) = theta_(2) = 45^(@)` `theta_(1) + theta_(2) = (45^(@) +alpha) +(45^(@) -alpha) = 90^(@)` `u_(1) = u_(2) = u rArr R_(1) = R_(2) = ?` `R_(1) = (u_(1)^(2)sin (theta_(1)+theta_(2)))/(g)` `rArr R_(1) = (u^(2)sin 90^(@))/(g) = (u^(2))/(g)` ........(i) Similarly, `R_(2) = (u_(2)^(2)sin (theta_(1)+theta_(2)))/(g)` `rArr R_(2) = (u^(2)sin 90^(@))/(g) = (u^(2))/(g)` .....(ii) The ratio of horizontal ranges `(R_(1))/(R_(2)) = (u^(2)//g)/(u^(2)//g) = 1:1 rArr R_(1):R_(2) = 1:1` |
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