1.

If the angle of shear is `30^(@)` for a cubical body and the change in length is 250 cm, then what must be the volume of this cubical body.

Answer» Given, angle of shear `=30^(@)`
and change in length, `DeltaL=250 cm =2.5 m`
`therefore` Shear strain, tan`phi=(DeltaL)/(L)implies"tan"30^(@)=(2.5)/(L)`
`L=(2.5)/("tan"30^(@))=(2.5)/(0.577)=4.332`
Volume, `V=L^(3)=81.309 m^(3)`


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