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If the angle of shear is `30^(@)` for a cubical body and the change in length is 250 cm, then what must be the volume of this cubical body. |
Answer» Given, angle of shear `=30^(@)` and change in length, `DeltaL=250 cm =2.5 m` `therefore` Shear strain, tan`phi=(DeltaL)/(L)implies"tan"30^(@)=(2.5)/(L)` `L=(2.5)/("tan"30^(@))=(2.5)/(0.577)=4.332` Volume, `V=L^(3)=81.309 m^(3)` |
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