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If the angle of shear is `30^(@)` for a cubical body and the change in length is 250 cm, then what must be the volume of this cubical body.A. `81.295 m^(3)`B. `71.309 m^(3)`C. `91.106 m^(3)`D. `83.266 m^(3)` |
Answer» Given, angle of shear `= 30^(@)` and change in length, `Delta L = 250 cm = 2.5 m` `:.` Shear strain, `tan theta = (Delta L)/(L)` ` implies tan 30^(@) = (2.5)/(L)` `L = (2.5)/(tan 30^(@)) = (2.5)/(0.577) = 4.332 m` Volume, `V = L^(3)` `= (4.332)^(3) = 81.295 m^(3)` |
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