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If the angle `theta` between the line `(x+1)/1=(y-1)/2=(z-2)/2` and the plane `2x-y+sqrt(pz)+4=0` is such that `sintheta=1/3`, then the values of p is (A) 0 (B) `1/3` (C) `2/3` (D) `5/3`A. `(-3)/(5)`B. `(5)/(3)`C. `(-4)/(3)`D. `(3)/(4)` |
Answer» Correct Answer - b The line is `(x+1)/(1)=(y-1)/(2)=(z-2)/(2)` and the plane is `2x-y+sqrtlamdaz+4=0`. If `theta` is the angle between the line and the plane, then `90^(@)-theta` is the angle between the line and normal to the plane. Thus, `cos(90^(@)-theta)=((1)(2)+(2)(-1)+(2)(sqrtlamda))/(sqrt(1+4+4)sqrt(4+1+lamda))` or `sintheta=(2-2+2sqrtlamda)/(3sqrt5+lamda)or(1)/(3)=(2sqrtlamda)/(3sqrt5+lamda)` or `sqrt(5+lamda)=2sqrtlamda` or `5+lamda=4lamda` or `3lamda=5` or `lamda=(5)/(3)` |
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