1.

Two mutually perpendicular straight lines through the origin from an isosceles triangle with the line `2x + y = 5`. Then the area of the triangle is

Answer» `AD=|(0+0-5)/sqrt(2^2+1^2)|=5/sqrt5=sqrt5`
in `/_ABD`
`tan 45^o=(AD)/(BD)=sqrt5/(BD)=1`
BD=`sqrt5`
so,
DC=`sqrt5`
BC=DC+`sqrt5`
BC=`sqrt5+sqrt5`
BC=`2sqrt5`
area of `/_ABC = 1/2*B*H`
=`1/2*BC*AD`
=`1/2*2sqrt5*sqrt5`
=`5units^2`


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