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If the angles of a triangle are x, y and `40^(@)` and the difference between the two angles x and y is `30^(@)`. Then, find the value of x and y. |
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Answer» Given that, x, y and `40^(@)` are the angles of a triangle. `:. " " x+y+40^(@)=180^(@)` `" " `[since, the sum of all the angles of a triangle is `180^(@)`] `rArr " " x+y=140^(@) " " ...(i)` Also, `" " x-y=30^(@) " " ...(ii)` On putting `x=85^(@)` in Eq. (i), we get `" " 85^(@)+y=140^(@)` `rArr " " y=55^(@)` Hence, the required values of x and y are `85^(@)` and `55^(@)`, respectively. |
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