InterviewSolution
Saved Bookmarks
| 1. |
The sum of a two–digit number and the number obtained by reversing the digits is 66. If the digits of the number differ by 2, find the number. How many such numbers are there? |
|
Answer» let tens digite of number is`x` let unit digit be`y` number= `(10x+y)` if no is reversed then unit digit `x` & tens digit `y` reversed number= `(10y+x)` acc to question `(10x+y) + (10y+x)= 66` `11x+11y=66` so, `x+y=6` now `x-y=2` or `y-x=2` case-1 `x-y=2 & x+y=6` by adding both, we get`2x= 8` `x=4` `y=2` so number will be `4*10=2 = 42` case 2 : `y-x=2 & x+y=6` by adding both, we get `2y= 8` `y=4` `x=2` now number will be `24` answer is 24 and 42 |
|