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If the angles of ∆ABC are in ratio 1:1:2, respectively (the largest angle being angle C), then the value of secA/cosec B – tanA/cot B is(a) 0(b) 1/2(c) 1(d) √3/2 |
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Answer» The correct option is (a) 0. 1x + 1x + 2x = 180°, x = 45°. ∠A, ∠B and ∠C are 45°, 45° and 90°resp. secA/cosec B – tanA/cot B = sec 45/cosec 45 – tan 45/cot 45 = √2/√2 – 1/1 = 1 - 1 = 0 |
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