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If the area of the circle `4x^(2)+4y^(2)-8x+16y+k=0` is `9pi` square units, then the value of k isA. 4B. 16C. -16D. `+-16` |
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Answer» Correct Answer - C We have, `4x^(2)+4y^(2)-8x+16y+k=0 rArr x^(2)+y^(2)-2x+4y+(k)/(4)=0` The radius of this circle is `sqrt(1+4-(k)/(4))=(sqrt(20-k))/(2)` We have, Area of the circle `= 9 pi rArr k = -16` |
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