InterviewSolution
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InterviewSolution
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If the average velocity of `N_(2)` molecules is `0.3 ms^(-1) at 27^(@) C` , then the velocity of `0.6 ms^(-1)` will take place atA. `273 K`B. `927 K`C. `1000 K`D. `1200 K` |
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Answer» Correct Answer - D According to the kinetic molecular theory of gases, we have `u_(aV) = sqrt((8RT)/(pi M))` i.e., `u_(aV) prop sqrt(T)` `:. ((u_(aV))_(1))/((u_(aV))_(2)) = sqrt((T_(1))/(T_(2)))` `(0.3 m s^(-1))/(0.6 m s^(-1)) = sqrt((27 + 273))/(T_(2))` `(1)/(2) = sqrt((300)/(T_(2)))` ltbrtgt or `(1)/(4) = (300)/(T_(2))` or `T_(2) = 1200 K` |
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