If the binding energy per nucleon in73Li and 42He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction p+73Li→242He, energy of proton must be

If the binding energy per nucleon in73Li and 42He nuclei are 5.60 MeV

1.	If the binding energy per nucleon in73Li and 42He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction p+73Li→242He, energy of proton must be
Answer» If the binding energy per nucleon in $\begin{matrix} 73 \end{matrix} L i$ and $\begin{matrix} 42 \end{matrix} H e$ nuclei are $5.60 MeV$ and $7.06 MeV$ respectively, then in the reaction $p + \begin{matrix} 73 \end{matrix} L i \to 2 \begin{matrix} 42 \end{matrix} H e$ , energy of proton must be

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If the binding energy per nucleon in73Li and 42He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction p+73Li→242He, energy of proton must be

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