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If the binding energy per nucleon of deuterium is 1.115 MeV, its mass defect in atomic mass unit isA. 0.0048B. 0.0024C. 0.0012D. 0.0006 |
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Answer» Correct Answer - b Binding energy per nucleon is `E_"bn"=E_b/A` For deuterium , A=2 `therefore ` 1.115 MeV=`E_b/2` or `E_b=2xx1.115` MeV or `E_b=DeltaMc^2` Mass defect, `DeltaM=(2xx1.115 )/931.5 u " " [because 1 u = 931.5 MeV//c^2]` =0.0024 u |
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