1.

If the bond energies of H-H, Br-Br and HBr are 433, 192 and 364 kJ mol^(-1) respectively, then DeltaH^@ for the reaction : H_(2(g)) + Br_(2(g)) rarr 2HBr_((g)) is

Answer»

`-261kJ`
`+103kJ`
`+261kJ`
`-103kJ`

ANSWER :D


Discussion

No Comment Found