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If the circle x^(2) + y^(2) + 4x - 6y + c = 0 bisects the circumference of the circle x^(2) + y^(2) - 6x + 4y - 12 = 0, then c is equal to |
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Answer» 16 `S^(1) -= x^(2) + y^(2) - 6x + 4y - 12 = 0` S = 0 bisects the CIRCUMFERENCE of `S^(1) = 0` `implies 2 g^(1) (g - g^(1)) + 2F^(1) (f - f^(1)) = c - c^(1)` `implies 2 (-3) (5) + 2 (-3, -2) - c + 12` `implies c = - 30 - 20 - 12` `:. c = - 62` |
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