1.

If the circle x^(2) + y^(2) + 4x - 6y + c = 0 bisects the circumference of the circle x^(2) + y^(2) - 6x + 4y - 12 = 0, then c is equal to

Answer»

16
24
`-42`
`-62`

SOLUTION :Given circle is , `S -= x^(2) + y^(2) + 4x - 6y + c - 0` and ,
`S^(1) -= x^(2) + y^(2) - 6x + 4y - 12 = 0`
S = 0 bisects the CIRCUMFERENCE of `S^(1) = 0`
`implies 2 g^(1) (g - g^(1)) + 2F^(1) (f - f^(1)) = c - c^(1)`
`implies 2 (-3) (5) + 2 (-3, -2) - c + 12`
`implies c = - 30 - 20 - 12`
`:. c = - 62`


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