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If the circle `x^2 + y^2 + 6x -2y + k = 0` bisects the circumference of the circle `x^2 + y^2 + 2x- 6y-15=0` , thenA. 21B. -21C. 23D. -23 |
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Answer» Correct Answer - D The equation of the common chord of the given circles is `4x+4y+(k+15)=0 ...(i)` Since `x^(2)+y^(2)+6x-2y+k=0` bisects the circumference of `x^(2)+y^(2)+2x-6y-15=0`. Therefore, (i) is a diameter of the circle `x^(2)+y^(2)+2x-6y-15=0`. `:. 4xx(-1)+4xx3+k+15=0 rArr k = - 23` |
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