If the circles x2+y2−16x−20y+164=r2 and (x−4)2+(y−7)2=36 inter – InterviewSolution

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1.	If the circles x2+y2−16x−20y+164=r2 and (x−4)2+(y−7)2=36 intersect at two distinct points, then :
Answer» If the circles $x^{2} + y^{2} - 16 x - 20 y + 164 = r^{2}$ and $(x - 4)^{2} + (y - 7)^{2} = 36$ intersect at two distinct points, then :

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